The New York Times has put together a fascinating map of the 2016 presidential election. This extremely detailed map allows anyone to drill down to the precinct level to see how their neighborhood voted.
As it turns out, downtown Lakewood was Clinton territory, and by a large margin.
Downtown Lakewood can be divided into four quadrants, using the intersection of Alameda and Wadsworth as the x and y axis. So there's a northeast quadrant (O'Kane Park), northwest quadrant (South Lakewood/Meadowlark), southeast quadrant (Belmar) and southwest quadrant (Belmar Park).
Belmar (the southeast quadrant) voted the most heavily for Clinton, with Hilary receiving 61% of the vote to Donald Trump's 27%. O'Kane Park (northeast) voted for Clinton 58% to 33%. South Lakewood/Meadowlark went for Clinton 57% to 35%, and Belmar Park voted for Clinton 56% to 35%.
The only area of downtown Lakewood that was evenly divided was a precinct surrounding Colorado Christian University. This small precinct sits in the northwest quadrant but is separate from the rest of the South Lakewood area. It voted for Clinton by only 45% to Trump's 44%.
In an a blog post from 2015, I described downtown Lakewood as a Democratic bastion within a more evenly divided city. This data from the New York Times confirms this and paints and even stronger picture of downtown Lakewood as a place where your neighbors are likely to be either Democrats or unaffiliated voters who vote Democratic in elections.
